document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1042680>Question 1042680</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi, I'm having a really difficult time understanding how to convert a Quadratic from Standard form to Vertex form. I've watched videos and have read multiple websites explaining it but either the videos are too fast, or the lesson is too confusing. I was wondering if there would be any way you could explain the steps in converting standard form to vertex form as simple as possible? Thank you so so much!! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #657703 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=657703\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Standard is ax^2+bx+c=0<BR>\n" );
document.write( "Start with x^2-2x-6=0<BR>\n" );
document.write( "The vertex x value is -b/2a<BR>\n" );
document.write( "Here, that would be -(-2)/2(1)=2/2=1<BR>\n" );
document.write( "So the x-value is 1<BR>\n" );
document.write( "Plug that into the equation and the y value is 1^2-(2)(1)-6=1-2-6=-7<BR>\n" );
document.write( "The vertex is (1,-7)<BR>\n" );
document.write( "The vertex form is y-=a(x-h)+k.  Change the sign of the x coordinate and keep the sign of the y.<BR>\n" );
document.write( "y=(x-1)^2-7<BR>\n" );
document.write( "You can always check by foiling out the square term.<BR>\n" );
document.write( "It is x^2-2x+1-7=x^2-2x-6<BR>\n" );
document.write( "-----------------------------------<BR>\n" );
document.write( "3x^2-6x-5=0<BR>\n" );
document.write( "divide the first two terms by 3 and put the 3 out front.<BR>\n" );
document.write( "3(x^2-2x)-5=0<BR>\n" );
document.write( "complete the square by taking half the x term and squaring it.  Whatever it is, subtract it from the constant to keep the equation balanced. We have added a 1 inside the parentheses and the whole inside term is multiplied by 3. We have to subtract 3 from the equation, too.<BR>\n" );
document.write( "3(x^2-2x+1)-5-3=3(x^2-2x+1)-8<BR>\n" );
document.write( "Now write it as the square.<BR>\n" );
document.write( "3(x-1)^2-8<BR>\n" );
document.write( "The vertex is at (1,-8), change the sign of the number after the x and keep the sign of the constant at the end.<BR>\n" );
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