document.write( "Question 1042482: A laboratory in Florida is interested in finding the mean chloride level for a healthy resident in the state. A random sample of 80 healthy residents has a mean chloride level of 99 mEq/L. If it is known that the chloride levels in healthy individuals residing in Florida have a standard deviation of 38 mEq/L, find a 99% confidence interval for the true mean chloride level of all healthy Florida residents.\r
\n" ); document.write( "\n" ); document.write( "so what is the lower limit and upper limit?\r
\n" ); document.write( "\n" ); document.write( "thanks for ur helping
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Algebra.Com's Answer #657695 by Boreal(15235)\"\" \"About 
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the ci is the interval (mean +/- t (0.995,df=79)*s/sqrt(n))
\n" ); document.write( "the t=2.64, s=38, n=80
\n" ); document.write( "99+/-2.64*38/sqrt(80); interval itself is 11.22
\n" ); document.write( "(88,110) or (87.88,110.22)
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