document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1042662>Question 1042662</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me to solve this question.\r<BR>\n" );
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document.write( "Question 1<BR>\n" );
document.write( "Suppose a certain population grows according to the formula N = NoE^kt, where N is number of people  (in millions) at time t (in years), No is the number of people (in millions) when an observation was first made, and k is a constant. Suppose the population increases from 2 million to 32 million in 80 years.\r<BR>\n" );
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document.write( "1.1 Use the given formula to determine the constant k (leave your answer in ln, if necessary).\r<BR>\n" );
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document.write( "1.2 Calculate the time in which the population will double.\r<BR>\n" );
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document.write( "Question 2<BR>\n" );
document.write( "Suppose that an amount of $5000 is invested for 3 years, and the interest is  compounded monthly at an annual rate of 10%. Write down a formula, simplified as far as possible, to represent the amount that the investment will be worth after 3 years.\r<BR>\n" );
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document.write( "Do not calculate the answer.\r<BR>\n" );
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document.write( "Thank for your help... </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #657693 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=657693\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> n=Noe^kt<BR>\n" );
document.write( "80,000,000=2,000,000e^k*80<BR>\n" );
document.write( "divide by 2000000<BR>\n" );
document.write( "40=e^80t<BR>\n" );
document.write( "ln of both sides<BR>\n" );
document.write( "ln 40=80t<BR>\n" );
document.write( "t=ln 40/80<BR>\n" );
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document.write( "doubling, n=2No<BR>\n" );
document.write( "2No=Noe^kt<BR>\n" );
document.write( "2=e^(ln40/80)*t<BR>\n" );
document.write( "ln 2=[ln (40)/80]t<BR>\n" );
document.write( "divide both sides by ln (40)/80. That inverts the denominator.<BR>\n" );
document.write( "80[ln 2/ln40]=t<BR>\n" );
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document.write( "A=Ao{1+r/n}^nt<BR>\n" );
document.write( "=5000{1+.10/12}^36<BR>\n" );
document.write( "=5000(1.08333}^36<BR>\n" );
document.write( "the exact answer is 5000{12.1/12)^36\r<BR>\n" );
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