Please help me solve this equation
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document.write( "1. Solve the following inequality for x:
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document.write( " 3x²-8x > 3\r\n" );
document.write( " 3x²-8x-3 > 0\r\n" );
document.write( "(x-3)(3x+1) > 0\r\n" );
document.write( "Critical numbers are the zeroes of\r\n" );
document.write( "the factors, 3, -1/3.\r\n" );
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document.write( "We graph the critical numbers on a number line.\r\n" );
document.write( "Since the inequality symbols are > and not
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document.write( "the critical numbers cannot be solutions, so we draw \r\n" );
document.write( "open circles at each critical number.\r\n" );
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document.write( "-----------o--------------------o-----------\r\n" );
document.write( "-2 -1
0 1 2 3 4 5\r\n" );
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document.write( "We test each interval.\r\n" );
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document.write( "We pick a test point on
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document.write( "We pick -1 and substitute it in\r\n" );
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document.write( " (x-3)(3x+1) > 0\r\n" );
document.write( " (-1-3)(3∙-1+1) > 0\r\n" );
document.write( " (-4)(-3+1) > 0\r\n" );
document.write( " (-4)(-2) > 0\r\n" );
document.write( " 8 > 0\r\n" );
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document.write( "That's true so we shade that interval on\r\n" );
document.write( "the number line:\r\n" );
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document.write( "<==========o--------------------o-----------\r\n" );
document.write( "-2 -1
0 1 2 3 4 5 \r\n" );
document.write( "Show that it has two different rational roots.\r\n" );
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document.write( "Next we pick a test point on
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document.write( "We pick 0 and substitute it in\r\n" );
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document.write( " (x-3)(3x+1) > 0\r\n" );
document.write( " (0-3)(3∙0+1) > 0\r\n" );
document.write( " (-3)(1) > 0\r\n" );
document.write( " -3 > 0\r\n" );
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document.write( "That's false so we DO NOT shade that interval on\r\n" );
document.write( "the number line. We still have this:\r\n" );
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document.write( "<==========o--------------------o-----------\r\n" );
document.write( "-2 -1
0 1 2 3 4 5\r\n" );
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document.write( "We test each interval.\r\n" );
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document.write( "We pick a test point on
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document.write( "We pick 4 and substitute it in\r\n" );
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document.write( " (x-3)(3x+1) > 0\r\n" );
document.write( "(4-3)(3∙4+1) > 0\r\n" );
document.write( " (1)(12+1) > 0\r\n" );
document.write( " (1)(13) > 0\r\n" );
document.write( " 13 > 0\r\n" );
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document.write( "That's true so we shade that interval on\r\n" );
document.write( "the number line:\r\n" );
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document.write( "<==========o--------------------o==========>\r\n" );
document.write( "-2 -1
0 1 2 3 4 5\r\n" );
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document.write( "So the solution in interval notation is\r\n" );
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document.write( "
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document.write( "2. Without solving the equation 3x² - 8x - 3 = 0
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document.write( "Show that it has two different rational roots.
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document.write( "[That's funny for we already had to solve it to\r\n" );
document.write( "get the critical values in the first problem. :) ]\r\n" );
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document.write( "But pretending we hadn't, we would just show that\r\n" );
document.write( "the discriminant is a perfect square:\r\n" );
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document.write( "Discriminant = b²-4ac = (-8)²-4(3)(-3) = 64+36 = 100\r\n" );
document.write( "which is 10², a perfect square, so we know that the\r\n" );
document.write( "quadratic has two rational roots. \r\n" );
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document.write( "Edwin
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