document.write( "Question 1042648: Find the standard equation of a circle which is centered at (-4,3) and tangent to the line y=-4x-30 \n" ); document.write( "
Algebra.Com's Answer #657660 by robertb(5830)\"\" \"About 
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Rewrite the equation of the line as 4x + y +30 = 0.\r
\n" ); document.write( "\n" ); document.write( "===> The distance of the center (-4,3) of the circle from the tangential line
\n" ); document.write( "4x + y +30 = 0 is given by \"d+=+abs%284%2A-4%2B3%2B30%29%2Fsqrt%284%5E2%2B1%5E2%29+=+17%2Fsqrt%2817%29+=+sqrt%2817%29\", which, incidentally, is also the radius of the circle.\r
\n" ); document.write( "\n" ); document.write( "===> the standard equation of circle is \"%28x%2B4%29%5E2%2B%28x-3%29%5E2+=+%28sqrt%2817%29%29%5E2\", or
\n" ); document.write( " \"%28x%2B4%29%5E2%2B%28x-3%29%5E2+=+17\".
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