document.write( "Question 1042622: A height-weight chart provides the following data: Height Weight
\n" ); document.write( "5' 5\" 150 lbs
\n" ); document.write( "5' 7\" 155 lbs
\n" ); document.write( "6' 1\" ? Assuming a linear equation fits the data, what would be the weight for the height of a 6' 1\" person?
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Algebra.Com's Answer #657611 by stanbon(75887)\"\" \"About 
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height-weight chart provides the following data: Height Weight
\n" ); document.write( "5' 5\" 150 lbs
\n" ); document.write( "5' 7\" 155 lbs
\n" ); document.write( "6' 1\" ? Assuming a linear equation fits the data, what would be the weight for the height of a 6' 1\" person?
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\n" ); document.write( "Note:: 5\" = 5/12 ft = 0.417
\n" ); document.write( "7\" = 7/12 ft = 0.583\r
\n" ); document.write( "\n" ); document.write( "You have two points::(5.417,150) ; (5.583.155)
\n" ); document.write( "slope = (155-150)/(5.583-5.417) = 5/0.166 = 30.12
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\n" ); document.write( "Equation:
\n" ); document.write( "Form:: y = mx + b
\n" ); document.write( "Solve for \"b\"::
\n" ); document.write( "155 = 30.12*5.583 + b'
\n" ); document.write( "b = -13.16
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\n" ); document.write( "F(x) = 30.12x - 13.16
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\n" ); document.write( "What would be the weight for the height of a 6' 1\" person?
\n" ); document.write( " 6'1\" = 6.083'
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\n" ); document.write( "F(6.083) = 30.12*6.083 - 13.16 = 170.06 lbs
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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