document.write( "Question 1042606: The given number [((1+i)i+1)i]i+1 is equivanlent to
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document.write( "A) 0
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document.write( "B) 1-i
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document.write( "C) 1
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document.write( "D) 1+i \n" );
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Algebra.Com's Answer #657600 by jim_thompson5910(35256) ![]() You can put this solution on YOUR website! Use the fact that i = sqrt(-1), so i^2 = -1\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "[((1+i)i+1)i]i+1 \n" ); document.write( "[(i+i^2+1)i]i+1 \n" ); document.write( "[(i+(-1)+1)i]i+1 \n" ); document.write( "[(i+0)i]i+1 \n" ); document.write( "[(i)*i]i+1 \n" ); document.write( "i^2*i+1 \n" ); document.write( "(-1)*i+1 \n" ); document.write( "-i+1 \n" ); document.write( "1-i\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The final answer is choice B) 1-i \n" ); document.write( " |