document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1042610>Question 1042610</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In how many ways can we pick a three-person committee from 7 people? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #657593 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=657593\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> There are 7 ways to fill slot A<BR>\n" );
document.write( "There are 6 ways to fill slot B (since we can't have any one person serve more than two posts)<BR>\n" );
document.write( "There are 5 ways to fill slot C\r<BR>\n" );
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document.write( "There are 7*6*5 = 42*5 = 210 different ways to fill the three slots (from a pool of 7). This is where order matters.\r<BR>\n" );
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document.write( "Since we're talking about a committee, this means order doesn't matter. Any one member doesn't outrank the other. \r<BR>\n" );
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document.write( "Since order doesn't matter, we have to divide by 6. Why 6? Because this is the number of ways to arrange 3 people. 3! = 3*2*1 = 6\r<BR>\n" );
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document.write( "210/6 = 35\r<BR>\n" );
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document.write( "The final answer is 35. There are 35 ways to pick three people from a pool of seven where order does NOT matter. </SPAN>\n" );
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