document.write( "Question 1042585: Hey, can someone please help? \r
\n" ); document.write( "\n" ); document.write( "Solve by completing the square: 9x=5x^2-1\r
\n" ); document.write( "\n" ); document.write( "I can normally figure out complete the square problems, but the leading coefficient in this is throwing me off! Please help! thank you!
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Algebra.Com's Answer #657579 by rothauserc(4718)\"\" \"About 
You can put this solution on YOUR website!
9x = 5x^2 - 1
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\n" ); document.write( "subtract 9x from both sides of =
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\n" ); document.write( "5x^2 -9x -1 = 0
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\n" ); document.write( "add 1 to both sides of =
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\n" ); document.write( "5x^2 -9x = 1
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\n" ); document.write( "divide both sides of = by 5
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\n" ); document.write( "x^2 -9x/5 = 1/5
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\n" ); document.write( "x^2 -9x/5 +81/100 = 1/5 +81/100
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\n" ); document.write( "(x - 9/10)^2 = 101/100
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\n" ); document.write( "x - 9/10 = square root(101) / 10
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\n" ); document.write( "x = (9/10) + (square root(101) / 10) = 1.905
\n" ); document.write( "x = (9/10) - (square root(101) / 10) = -0.105
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