document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1042591>Question 1042591</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In a shipment of 190 items, 3 are found defective.  If 3 items are selected at random, what is the probability the shipment will be rejected if 1 of the 3 is defective? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #657568 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=657568\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> This is 1 of the 3, not at least 1 of the three, I am assuming.<BR>\n" );
document.write( "3 ways 1 of the 3 can be defective, the first, second, or third.<BR>\n" );
document.write( "3*(3/190)*(187/189)(186/188); the 3 takes care of the possibility the second is defective (187/190)(3/189)(186/188) and the third is defective (187/190)(186/189)(3/188).  The denominators and numerators are the same but ordered differently.<BR>\n" );
document.write( "The probability is 3*3*187*186/190*189*188=<BR>\n" );
document.write( "313038/67510180=0.0464.<BR>\n" );
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document.write( "a check would be along the lines that about 1/63 is defective, and 3 chances of doing that are 3/63, which is 1/21, of just under 5%, which fits with the answer. </SPAN>\n" );
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