document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1042548>Question 1042548</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A and B are two independent events. The probability that both occur simultaneously is 1/6 and the\r<BR>\n" );
document.write( "\n" );
document.write( "probability that neither occurs is 1/3, then P(A) + P(B) = *? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #657518 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=657518\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> P(A&#8745;B) = 1/6 and 1 - P(A&#8746;B) = 1/3, as given.\r<BR>\n" );
document.write( "\n" );
document.write( "==> 1 - P(A&#8746;B) = 1 - (P(A) + P(B) -  P(A&#8745;B)) = 1/3.\r<BR>\n" );
document.write( "\n" );
document.write( "==> 1 + P(A&#8745;B) - 1/3 = P(A) + P(B)\r<BR>\n" );
document.write( "\n" );
document.write( "==> 1 + 1/6 -1/3 = P(A) + P(B)\r<BR>\n" );
document.write( "\n" );
document.write( "==> P(A) + P(B) = 5/6.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );