document.write( "Question 1042485: Using either the substitution or elimination method solve this problem. A certain aircraft can fly 1330 miles with the wind in 5 hours and travel the same distance against the wind in 7 hours. What is the speed of the wind?\r
\n" );
document.write( "\n" );
document.write( "can you please explain each step so I can understand where everything comes from? Thanks \n" );
document.write( "
Algebra.Com's Answer #657460 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! speed of plane=P \n" ); document.write( "speed of wind=W \n" ); document.write( "To fly 1330 miles in 5 hours means 1330/5=266 mph \n" ); document.write( "to fly 1330 miles in 7 hours means 1330/7=190 mph \n" ); document.write( "The wind is added or subtracted to the plane's speed. \n" ); document.write( "P+W=266; here the wind speed is added to the plane's speed. \n" ); document.write( "P-W=190; subtracted. \n" ); document.write( "Add the two, and the W will disappear \n" ); document.write( "2P=456 \n" ); document.write( "divide by 2 both sides \n" ); document.write( "P=228 mph. \n" ); document.write( "P+W=266 \n" ); document.write( "W=266-228=38 mph. ANSWER \n" ); document.write( "P-W=228=38=190 mph, the speed of the plane against the wind. \n" ); document.write( " |