document.write( "Question 1042485: Using either the substitution or elimination method solve this problem. A certain aircraft can fly 1330 miles with the wind in 5 hours and travel the same distance against the wind in 7 hours. What is the speed of the wind?\r
\n" ); document.write( "\n" ); document.write( "can you please explain each step so I can understand where everything comes from? Thanks
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Algebra.Com's Answer #657460 by Boreal(15235)\"\" \"About 
You can put this solution on YOUR website!
speed of plane=P
\n" ); document.write( "speed of wind=W
\n" ); document.write( "To fly 1330 miles in 5 hours means 1330/5=266 mph
\n" ); document.write( "to fly 1330 miles in 7 hours means 1330/7=190 mph
\n" ); document.write( "The wind is added or subtracted to the plane's speed.
\n" ); document.write( "P+W=266; here the wind speed is added to the plane's speed.
\n" ); document.write( "P-W=190; subtracted.
\n" ); document.write( "Add the two, and the W will disappear
\n" ); document.write( "2P=456
\n" ); document.write( "divide by 2 both sides
\n" ); document.write( "P=228 mph.
\n" ); document.write( "P+W=266
\n" ); document.write( "W=266-228=38 mph. ANSWER
\n" ); document.write( "P-W=228=38=190 mph, the speed of the plane against the wind.
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