document.write( "Question 1042417: (i) a car leaves town A at 09 50 and travels towards town B at an average speed of 44km/h. at what time will it reach town which is 66km away? (ii) on reaching town B, it continues its journey towards town c but reduces its speed by 7km/h. it reaches town C at 13 20. find the distance between town B and town C. (iii) calculate the average speed for the whole journey, between town A and town C
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Algebra.Com's Answer #657379 by chen.aavaz(62)\"\" \"About 
You can put this solution on YOUR website!
Time needed for the car to travel from A to B:
\n" ); document.write( "t=S/V where S is the distance between the two towns and V the car speed.
\n" ); document.write( "Therefore t=66/44 = 1.5h, so it reaches B 1.5 hour after 9:50, that is, 11:20.\r
\n" ); document.write( "\n" ); document.write( "The reduced speed after it reaches B is \"V1%3A+%2844-7%29km%2Fh=37km%2Fh\".
\n" ); document.write( "The car reaches town C at 13:20, that is, t1=2 hours after 11:20.
\n" ); document.write( "Distance S1 between B and C:
\n" ); document.write( "\"S1=V1%2At1+=+37%2A2+km+=+74+km\".\r
\n" ); document.write( "\n" ); document.write( "Average speed: (total distance)/(total time) =
\n" ); document.write( "\"%2866%2B74%29%2F%281.5%2B2%29=40km%2Fh\"\r
\n" ); document.write( "\n" ); document.write( "I hope I explained it clear enough!
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