document.write( "Question 1042370: Please help me slove this mixture\r
\n" ); document.write( "\n" ); document.write( "You need a 10% alcohol solution. On hand, you have a 50 mL of a 30% alcohol mixture. How much pure water will you need to add to obtain the desired solution?\r
\n" ); document.write( "\n" ); document.write( "A) Write an equation using the information as it is given above that can be used to solve this problem. Use
\n" ); document.write( "x
\n" ); document.write( "x as your variable to represent the amount of pure water you need to use.
\n" ); document.write( "Equation:
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\n" ); document.write( "\n" ); document.write( "B) You will need \r
\n" ); document.write( "\n" ); document.write( " mL of pure water
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\n" ); document.write( "\n" ); document.write( " mL of the desired 10% solution
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Algebra.Com's Answer #657365 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
You need a 10% alcohol solution. On hand, you have a 50 mL of a 30% alcohol mixture.
\n" ); document.write( " How much pure water will you need to add to obtain the desired solution?
\n" ); document.write( "A) Write an equation using the information as it is given above that can be used to solve this problem. Use x as your variable to represent the amount of pure water you need to use.
\n" ); document.write( ":
\n" ); document.write( "The mixture you have is 30% alcohol, therefore it is 70% water. (total is 100%)
\n" ); document.write( "Result is to be 10% alcohol, therefore it is 90% water
\n" ); document.write( ":
\n" ); document.write( "the equation using the decimal form of percent, based on the amt of water
\n" ); document.write( ".70(50) + x = .90(x+50)
\n" ); document.write( "35 + x = .90x + 45
\n" ); document.write( "x - .9x = 45 - 35
\n" ); document.write( ".10x = 10
\n" ); document.write( "x = 10/.1
\n" ); document.write( "x = 100 ml of pure water required
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