document.write( "Question 1042390: (PvQ)&R
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document.write( "(R&P)>S
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document.write( "(Q&R)>S
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document.write( "Therefore,
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document.write( "S \n" );
document.write( "
Algebra.Com's Answer #657355 by solver91311(24713)![]() ![]() You can put this solution on YOUR website! \r \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( " 1. (P v Q) & R\r\n" ); document.write( " 2. R & P -> S\r\n" ); document.write( " 3. Q & R -> S | S\r\n" ); document.write( "\r\n" ); document.write( " 4. P v Q 1 Conjunction Elimination\r\n" ); document.write( " 5. R 1 Conjunction Elimination\r\n" ); document.write( "| 6. P ACP, Case 1\r\n" ); document.write( "| 7. R & P 5, 6 Conjunction Addition\r\n" ); document.write( "| 8. S 7, 2 Modus Ponens\r\n" ); document.write( "| 9. Q ACP, Case 2\r\n" ); document.write( "| 10. Q & R 9, 6 Conjunction Addition\r\n" ); document.write( "| 11. S 10, 3 Modus Ponens\r\n" ); document.write( "12. S 8, 11 Exhaustive cases\r\n" ); document.write( "\r\n" ); document.write( "\r \n" ); document.write( "\n" ); document.write( "John \n" ); document.write( " \n" ); document.write( "My calculator said it, I believe it, that settles it \n" ); document.write( " ![]() \n" ); document.write( " |