document.write( "Question 1042363: The sum of first three terms of a finite geometric series is -(7/10) and their product is -(1/125). [Hint: Use a/r, a, and ar to represent the first three terms, respectively.] The three numbers are _____, _____, and _____. \n" ); document.write( "
Algebra.Com's Answer #657329 by stanbon(75887)\"\" \"About 
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The sum of first three terms of a finite geometric series is -(7/10) and their product is -(1/125). [Hint: Use a/r, a, and ar to represent the first three terms, respectively.] The three numbers are _____, _____, and _____.
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\n" ); document.write( "a/r + a + ar = -7/10
\n" ); document.write( "(a/r)*a*(ar) = -1/125
\n" ); document.write( "---------------------------
\n" ); document.write( "a^3 = -1/125
\n" ); document.write( "a = -1/5
\n" ); document.write( "------------------------
\n" ); document.write( "Solve for \"r\"::
\n" ); document.write( "a/r = (-1/5)/r = -1/(5r)
\n" ); document.write( "a = -1/5
\n" ); document.write( "a*r = (-1/5)r
\n" ); document.write( "------
\n" ); document.write( "So, -1/(5r) + (-1/5) + -r/5 = -7/10
\n" ); document.write( "Multiply thru by 10r to get:
\n" ); document.write( "-2 - 2r -2r^2 = -7r
\n" ); document.write( "----
\n" ); document.write( "2r^2 -5r + 2 = 0
\n" ); document.write( "----
\n" ); document.write( " r = 2
\n" ); document.write( "-----------------------------------
\n" ); document.write( "1st term:: a/r = (-1/5)/(2) = -1/10
\n" ); document.write( "2nd term:: a = -1/5 = -2/10
\n" ); document.write( "3rd term:: a*r = (-2/10)(2) =-4/10
\n" ); document.write( "Note: Sum = -7/10
\n" ); document.write( "-------------
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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