document.write( "Question 1042354: We want to select a committee of five members from a group of five women and six men. The order of selection is irrelevant. \r
\n" ); document.write( "\n" ); document.write( "How many committees can we make consisting of two women and three men? \r
\n" ); document.write( "\n" ); document.write( "I have tried this several ways but I am doing something wrong. Can someone show me as I have more to do like this for my upcoming summer final. \n" ); document.write( "

Algebra.Com's Answer #657315 by chen.aavaz(62) $\"\"$ $\"About$

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First we calculate how many committees of 2 women we can make out of the 5 women:\r
\n" ); document.write( "\n" ); document.write( " $\"W+=+5%21%2F%285-2%29%212%21+=+10\"$ hence we can have 10 such committees
\n" ); document.write( "Similarly, we calculate the number of committees of 3 out of 6 men:
\n" ); document.write( " $\"M+=+6%21%2F%286-3%29%213%21+=+20\"$
\n" ); document.write( "Now we must combine each of the first 10 women committees with each of the 20 men committees; thus the total number must be $\"10%2A20=200\"$ \n" ); document.write( "

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