document.write( "Question 1042354: We want to select a committee of five members from a group of five women and six men. The order of selection is irrelevant. \r
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document.write( "How many committees can we make consisting of two women and three men? \r
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document.write( "I have tried this several ways but I am doing something wrong. Can someone show me as I have more to do like this for my upcoming summer final. \n" );
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Algebra.Com's Answer #657314 by jorel555(1290)![]() ![]() ![]() You can put this solution on YOUR website! You have 5 women to choose from. 5 choose 2 is 5!/3!2!, which equals 10. Similarly, for men it's 6 choose 3, which is 20. \n" ); document.write( "20 x 10=200 different ways of choosing 2 women and 3 men. ☺☺☺☺ \n" ); document.write( " |