document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1042258>Question 1042258</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The two non-parallel sides of an isosceles trapezoid are each 7 feet long. The longer of the two bases measures 22 feet long. The sum of the base angles is 140°.\r<BR>\n" );
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document.write( "(a) Find the length of the diagonal.\r<BR>\n" );
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document.write( "(b) Find the length of the shorter base.\r<BR>\n" );
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document.write( "Show all your work and explain how you arrived at your answer. Round answers to the nearest hundredth. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #657243 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=657243\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> It helps to draw it.<BR>\n" );
document.write( "Since it is isosceles, the angles are the same and must be 70 degrees.<BR>\n" );
document.write( "sin 70=x/7, and that is the height of the trapezoid, or 6.58 feet<BR>\n" );
document.write( "cos 70=y/7, and that is half the distance that the longer base is over the shorter base.<BR>\n" );
document.write( "y=7 cos 70=2.39 feet<BR>\n" );
document.write( "The longer base is 4.79 (rounding) feet greater than the shorter base, so the shorter is 17.21 feet long.<BR>\n" );
document.write( "The diagonal:  The base of the right triangle for which the diagonal is the hypotenuse is 22-2.39=19.61 feet long.  The height is 6.58 feet.  Square both and have 384.390+43.268=427.658.  The hypotenuse is the square root of that.<BR>\n" );
document.write( "The square root of that is 20.68 feet. Diagonal. </SPAN>\n" );
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