document.write( "Question 1042237: A city zoo borrowed $2,000,000 at simple annual interest to construct a breeding facility. Some of the money was borrowed at 7%, some at 8%, and some at 11%. Use a system of linear equations to determine how much was borrowed at each rate given that the total annual interest was $164,500 and the amount borrowed at 7% was twice the amount borrowed at 11%. Solve the system of linear equations using matrices. \n" ); document.write( "
Algebra.Com's Answer #657213 by addingup(3677)\"\" \"About 
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2,000,000 was borrowed:
\n" ); document.write( "0.07x+0.11(1/2x)
\n" ); document.write( "+
\n" ); document.write( "0.08(2,000,000-(x+1/2x)
\n" ); document.write( "= 164,500
\n" ); document.write( ":
\n" ); document.write( "(0.07+0.055)x+0.08(2,000,000-1 1/2x) = 164,500
\n" ); document.write( "0.125x+160000-0.12x = 164,500
\n" ); document.write( "0.005x = 4,500 = 900,000 is the amount borrowed at 7%
\n" ); document.write( "1/2*900,000 = 450,000 is the amount borrowed at 11%
\n" ); document.write( "2,000,000-1,350,000 = 650,000 is the amount borrowed at 8%
\n" ); document.write( "-------------------------------
\n" ); document.write( "Check:
\n" ); document.write( "900,000*.07 = 63,000
\n" ); document.write( "450,000*.11 = 49,500
\n" ); document.write( "650,000*.08 = 52,000
\n" ); document.write( "Total. . . . 164,500 Correct
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\n" ); document.write( "John
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