document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1042235>Question 1042235</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The figure below represents a semicircle with diameter AB and centre O. The radius of the semicircle is 3 cm. Taking pi to be 3.14, calculate<BR>\n" );
document.write( "a) the area of the shaded figure <BR>\n" );
document.write( "b) the perimeter of the shaded figure  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #657210 by </B><A HREF=/tutors/aboutme.mpl?userid=chen.aavaz><B>chen.aavaz(62)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=chen.aavaz><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=657210\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> My friend, there is no figure, so I will assume that we are talking about a semicircle and a diameter and the shaded area is the inside.\r<BR>\n" );
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document.write( "The area of the shaded figure is half of the area of the circle, that is, <BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A+=+%281%2F2%29%2Api%2Ar%5E2+=+%281%2F2%29%2A3.14%2A3%5E2+=+14.13 ALIGN=MIDDLE  ALT=\"A+=+%281%2F2%29%2Api%2Ar%5E2+=+%281%2F2%29%2A3.14%2A3%5E2+=+14.13\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "The perimeter is that of a semicircle plus the length of the diameter:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=P=%281%2F2%29%2A2%2Api%2Ar%2B2%2Ar+=+3.14%2A3%2B6+=+15.42 ALIGN=MIDDLE  ALT=\"P=%281%2F2%29%2A2%2Api%2Ar%2B2%2Ar+=+3.14%2A3%2B6+=+15.42\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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