document.write( "Question 13126: I am a mom who is trying to help my 11th grade daughter with her algebra. I remember a while back there being a way to get rid of fractions in an algebra problem but can't for the life of me remember how now. The problem we are trying to figure out is: 9/2(x+3)=27
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document.write( "For some reason I want to put the problem like this to rid the fraction:
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document.write( "9/2 (x/2+3/2)=27/2 I then would do the following but answer not working:
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document.write( "18(2x+6)=54
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document.write( "36x+108=54
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document.write( "36x+108-108=54-108
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document.write( "36x=-54
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document.write( "36x/36=-54/36
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document.write( "x=1.5\r
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document.write( "I know this isn't right because when I tried to plug it into the equation it didn't work. Could someone please tell me what I am doing wrong to rid problems of fractions? \n" );
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Algebra.Com's Answer #6572 by pwac(253)![]() ![]() ![]() You can put this solution on YOUR website! 9/2(x+3)=27 Hi mom.Deal with the bracket first. \n" ); document.write( "Look at left side as \n" ); document.write( "9times(x+3)=9x+27.This is all over 2.You now have: \n" ); document.write( "9x+27/2 =27 Multiply both sides by 2 \n" ); document.write( "9x+27=54 Subtract 27 from both sides \n" ); document.write( "9x=27 Divide both sides by 9 \n" ); document.write( "x=27/9 \n" ); document.write( "x=3 \n" ); document.write( "Plug into original to check 9/2 X 3+3 = 27 \n" ); document.write( " 4.5 X 6 does =27 \n" ); document.write( "Hope this helps \n" ); document.write( "Pete \n" ); document.write( " |