document.write( "Question 1042230: A city commission has proposed two tax bills. The firs bill requires that a homeowner pays $1800 plus 3% of the assessed home value in taxes. The second bill requires taxes of $200 8% of the assessed home value. what price range of the home assessment would make the first bill a better deal for the homeowner? \n" ); document.write( "

Algebra.Com's Answer #657196 by Boreal(15235) $\"\"$ $\"About$

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First is 1800+0.03x, where x is home value
\n" ); document.write( "Second is 200+0.08x
\n" ); document.write( "set them equal and solve for x
\n" ); document.write( "1800+0.03x=200+0.08x
\n" ); document.write( "1600=0.05x
\n" ); document.write( "divide by 0.05 (or multiply by 20)
\n" ); document.write( "32000=x
\n" ); document.write( "That is where they are equal.
\n" ); document.write( "One can try 30,000 and compare both
\n" ); document.write( "The first would be 1800+0.03(30,000)=2700
\n" ); document.write( "The second would be 200+0.08(200)=360
\n" ); document.write( "So for house prices > 32,000, plan 1 would be better.
\n" ); document.write( "------------------------------
\n" ); document.write( "Set it as an inequality.
\n" ); document.write( "1800+0.03x<200+0.08x
\n" ); document.write( "-0.05x<-1600
\n" ); document.write( "divide by -20 and flip inequality signs
\n" ); document.write( "x>$32,000
\n" ); document.write( " \n" ); document.write( "

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