document.write( "Question 1042183: The length of a rectangle is 2 more than twice its width. If the area of the rectangle is 24 sq. meters, find its dimension \n" ); document.write( "

Algebra.Com's Answer #657131 by addingup(3677) $\"\"$ $\"About$

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2 more than twice its width. If the area of the rectangle is 24
\n" ); document.write( "Area of the rectangle:
\n" ); document.write( "L*W = A
\n" ); document.write( ":
\n" ); document.write( "L = 2W
\n" ); document.write( "Therefore:
\n" ); document.write( "2W*W = 24
\n" ); document.write( "2W^2 = 24
\n" ); document.write( "W^2 = 12
\n" ); document.write( "W = sqrt12
\n" ); document.write( "or
\n" ); document.write( "W = -sqrt12
\n" ); document.write( "W = 3.464
\n" ); document.write( "or
\n" ); document.write( "W = -3.464
\n" ); document.write( "Since we are looking for a positive number, the answer is:
\n" ); document.write( "W = 3.464
\n" ); document.write( "--------------------
\n" ); document.write( "Check:
\n" ); document.write( "L*W = 24
\n" ); document.write( "2W*W = 24
\n" ); document.write( "2(3.464)*3.464 = 24
\n" ); document.write( "6.928*3.464 = 24 Correct.
\n" ); document.write( "John \n" ); document.write( "

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