document.write( "Question 1042166: A large shipment of watermelons has weights that are normally distributed with a standard deviation of 0.71 kg. The probability that a watermelon weights less than 2.1 kg is 10.2%. The mean shipment to the nearest hundredth of a kg is \n" ); document.write( "
Algebra.Com's Answer #657103 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "A large shipment of watermelons has weights that are normally distributed with a standard deviation of 0.71 kg. The probability that a watermelon weights less than 2.1 kg is 10.2%. The mean shipment to the nearest hundredth of a kg is ? \n" ); document.write( "---------------------------------- \n" ); document.write( "Find the z-value with a left tail of 10.2% \n" ); document.write( "invNorm(0.102) = -1.2703 \n" ); document.write( "Using x = z*s + u, \n" ); document.write( "2.1 = -1.2703*0.71 + u \n" ); document.write( "----------- \n" ); document.write( "u = 3.00 \n" ); document.write( "------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "--------------- \n" ); document.write( " \n" ); document.write( " |