document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1042126>Question 1042126</A>: <I><SPAN STYLE=\"word-break: break-all;\"> CotA =4/3 and (a+b)=90degree find the value of tanB = ?<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #657085 by </B><A HREF=/tutors/aboutme.mpl?userid=Aldorozos><B>Aldorozos(172)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Aldorozos><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=657085\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Tan(A+B) = (TanA+TanB)/(1-TanATanB)<BR>\n" );
document.write( "Please Watch this video:<BR>\n" );
document.write( "https://www.youtube.com/watch?v=igNTc-G_77k<BR>\n" );
document.write( "We know that Tan = 1/cot\r<BR>\n" );
document.write( "\n" );
document.write( "If (a+b) = 90 then tan(a+b)= tan 90<BR>\n" );
document.write( "We know that tan 90 = 0 then tan(a+b)= 0\r<BR>\n" );
document.write( "\n" );
document.write( "We know that  Tan(A+B) = (TanA+TanB)/(1-TanATanB)= 0 for <BR>\n" );
document.write( "(TanA+TanB)/(1-TanATanB)to be equal to zero the numerator has to be equal to zero which means  TanA+TanB = 0. We already know what the tan of a is (Tan a = 1/CotA) This means that tan a = 1/(4/3) = 3/4 (Please note that the problem has already given us the value of Cot A which is 4/3\r<BR>\n" );
document.write( "\n" );
document.write( "Therefore Tan A + Tan B = 0 replacing Tan A with 3/4 we get<BR>\n" );
document.write( "Tan B + 3/4 = 0. Therefore Tan B = -3/4\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );