document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1042132>Question 1042132</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the product of two positive numbers is 5/6 and their quotient is 15/8. calculate the numbers </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #657081 by </B><A HREF=/tutors/aboutme.mpl?userid=Aldorozos><B>Aldorozos(172)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Aldorozos><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=657081\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x*y = 5/6<BR>\n" );
document.write( "x/y = 15/8\r<BR>\n" );
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document.write( "In x/y = 15/8 multiply both sides by y to get ride of the denominator and find out what x is in terms of y\r<BR>\n" );
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document.write( "x = 15/8 * y<BR>\n" );
document.write( "Now that we know what x is in terms of Y we replace x in x*y = 5/6 and we get<BR>\n" );
document.write( "(15/8 * y)* y = 5/6\r<BR>\n" );
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document.write( "y^2 *15/8 = 5/6 Therefore y^2 = 5/6 *8/15  (here we multiplied both sides by 15/8 to isolate y^2)\r<BR>\n" );
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document.write( "Now we have y^2 = 4/9 Therefore y = +2/3 and -2/3<BR>\n" );
document.write( "Now that we have y we replace y in x*y = 5/6 with +2/3 and -2/3 and we get two values for x which are 5/4 and -5/4<BR>\n" );
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