document.write( "Question 1042119: Two pipes together can fill the reservoir in 6 hours and 40 minutes. Find the time each alone will take to fill the reservoir if one of the pipes can fill it in 3 hours less than the other. \n" ); document.write( "

Algebra.Com's Answer #657064 by stanbon(75887) $\"\"$ $\"About$

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Two pipes together can fill the reservoir in 6 hours and 40 minutes. Find the time each alone will take to fill the reservoir if one of the pipes can fill it in 3 hours less than the other.
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\n" ); document.write( "Note:: 6 hr 40 min = 6 2/3 hrs = 20/3 hrs/job
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\n" ); document.write( "together rate:: 3/20 job/hr
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\n" ); document.write( "slower pipe rate:: 1/x job/hr
\n" ); document.write( "faster pipe rate:: 1/(x-3) job/hr
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\n" ); document.write( "Equation::
\n" ); document.write( "rate + rate = together rate
\n" ); document.write( "1/x + 1/(x-3) = 3/20
\n" ); document.write( "20(x-3) + 20x = 3x(x-3)
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\n" ); document.write( "40x - 60 = 3x^2 - 9x
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\n" ); document.write( "3x^2 - 49x + 60 = 0
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\n" ); document.write( "x = 15 hr (slower time)
\n" ); document.write( "x-3 = 12 hr (faster time)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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