document.write( "Question 90292This question is from textbook Beginning Al
\n" ); document.write( ": The length of a rectangle is 1 cm longer than its width. If the diagonal of the rectangle is 4 cm, what are the dimensions (the length and the width) of the rectangle?\r
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Algebra.Com's Answer #65705 by vertciel(183)\"\" \"About 
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Hello there,\r
\n" ); document.write( "\n" ); document.write( "Denote:\r
\n" ); document.write( "\n" ); document.write( "Width = w\r
\n" ); document.write( "\n" ); document.write( "Length = 1 + w\r
\n" ); document.write( "\n" ); document.write( "A rectangle can form two isosceles triangles, so we can use the Pythagorean Theorem to find the length and width.\r
\n" ); document.write( "\n" ); document.write( "a^2 + b^2 = c^2\r
\n" ); document.write( "\n" ); document.write( "w^2 + (w + 1)^2 = 4^2\r
\n" ); document.write( "\n" ); document.write( "2w^2 + 2w + 1 = 16\r
\n" ); document.write( "\n" ); document.write( "2w^2 + 2w - 15 = 0\r
\n" ); document.write( "\n" ); document.write( "Find w, and plug them into the short equations for width and length. There you are.
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