document.write( "Question 1042102: √3 tan A = 3 sinA to find value of cos square A -sin square A \n" ); document.write( "
Algebra.Com's Answer #657042 by ikleyn(52915)\"\" \"About 
You can put this solution on YOUR website!
.
\n" ); document.write( "sqrt(3)*tan(A) = 3*sin(A). Find value of \"cos%5E2%28A%29+-sin%5E2%28A%29\".
\n" ); document.write( "~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Notice that I edited your post . . . \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\r\n" );
document.write( "\"sqrt%283%29%2Atan%28A%29\" = \"3%2Asin%28A%29\"  --->  \"sqrt%283%29%2A%28sin%28A%29%2Fcos%28A%29%29\" = \"3%2Asin%28A%29\"  --->  \"1%2Fcos%28A%29\" = \"3%2Fsqrt%283%29\"  --->  cos(A) = \"sqrt%283%29%2F3%29\".\r\n" );
document.write( "\r\n" );
document.write( "If  cos(A) = \"sqrt%283%29%2F3%29\"  then  sin(A) = \"sqrt%281-cos%5E2%28A%29%29\" = \"sqrt%281-%28sqrt%283%29%2F3%29%5E2%29\" = \"sqrt%281-3%2F9%29\" = \"sqrt%286%2F9%29\" = +/-\"sqrt%286%29%2F3\".\r\n" );
document.write( "\r\n" );
document.write( "Now,  \"cos%5E2%28A%29+-sin%5E2%28A%29\" = \"%28sqrt%283%29%2F3%29%5E2\" - \"%28sqrt%286%29%2F3%29%5E2\" = \"3%2F9+-+6%2F9\" = \"-3%2F9\" = \"-1%2F3\".\r\n" );
document.write( "\r\n" );
document.write( "Answer.  \"cos%5E2%28A%29+-sin%5E2%28A%29\" =  \"-1%2F3\".\r\n" );
document.write( "

\n" ); document.write( "
\n" ); document.write( "
\n" );