document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1042095>Question 1042095</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many grams of gold should a coin of thirty - seven percent gold be when combined with a four grams pure gold necklace,  when it forms a metal that is seventy - seven percent gold? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #657026 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=657026\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> ow many grams of gold should a coin of thirty - seven percent gold be when combined with a four grams pure gold necklace, when it forms a metal that is seventy - seven percent gold? <BR>\n" );
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document.write( "gold + gold = gold<BR>\n" );
document.write( "0.37x + 1*4 = 0.77(x+4)<BR>\n" );
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document.write( "37x + 100*4 = 77x + 44*4<BR>\n" );
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document.write( "40x = 56*4<BR>\n" );
document.write( "x = 56/10<BR>\n" );
document.write( "x = 5.6 grams (amt of 37% needed)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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