document.write( "Question 90541: PLEASE HELP ME WITH THIS QUESTION!! it is really confusing. I NEED ANSWER FOR MY TEACHER. SHE WANTS TO KNOW.
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document.write( "1Q: Two angles are complementary and in the ration of 1:5. Find the measure of each angle.
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document.write( "2Q: The larger og two complementary angles is 30 degrees less than twice the smaller. Find the measure of each angle.
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document.write( "THANK YOU!!! \n" );
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Algebra.Com's Answer #65697 by vertciel(183)![]() ![]() ![]() You can put this solution on YOUR website! Hello there,\r \n" ); document.write( "\n" ); document.write( "1. Let's express the smaller angle as \"s\", since it's smaller. The ratio is 1:5 so you would set up the following equation:\r \n" ); document.write( "\n" ); document.write( "s + 5s = 90 (complementary angle = 90°)\r \n" ); document.write( "\n" ); document.write( "In this case, s would be the smaller angle, and 5s would be the larger angle. I'll leave it to you now.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2. We will denote \"s\" as the smaller angle and \"L\" as the larger angle\".\r \n" ); document.write( "\n" ); document.write( "s = s\r \n" ); document.write( "\n" ); document.write( "L = 2s - 30 \r \n" ); document.write( "\n" ); document.write( "They are complementary so s + L = 90. \r \n" ); document.write( "\n" ); document.write( "There you are.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |