document.write( "Question 1042051: Last problem I'm having issues with is\r
\n" ); document.write( "\n" ); document.write( "e^(12-5x)-7=123\r
\n" ); document.write( "\n" ); document.write( "I got as far as adding 7 to both sides and got stuck \n" ); document.write( "
Algebra.Com's Answer #656952 by Edwin McCravy(20054)\"\" \"About 
You can put this solution on YOUR website!
\r\n" );
document.write( "\"e%5E%2812-5x%29-7=123\"\r\n" );
document.write( "\r\n" );
document.write( "\"e%5E%2812-5x%29=130\"\r\n" );
document.write( "\r\n" );
document.write( "Learn to write exponential equations as logarithm equations:\r\n" );
document.write( "\r\n" );
document.write( "\"B%5EC=A\" and \"C=log%28B%2CA%29\" are equivalent.\r\n" );
document.write( "\r\n" );
document.write( "So \"e%5E%2812-5x%29=130\" is equivalent to \r\n" );
document.write( "\r\n" );
document.write( "\"12-5x=log%28e%2C%28130%29%29\"\r\n" );
document.write( "\r\n" );
document.write( "An abbreviation for loge is ln, so\r\n" );
document.write( "\r\n" );
document.write( "\"12-5x=ln%28130%29\"\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "\"x+=+-ln%28130%29%2F5%2B12%2F5\"\r\n" );
document.write( "\r\n" );
document.write( "Get your calculator:\r\n" );
document.write( "\r\n" );
document.write( "\"x+=+1.42649311\"\r\n" );
document.write( "\r\n" );
document.write( "Edwin
\n" ); document.write( "
\n" );