document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1042042>Question 1042042</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am having a few issues if someone could help. The first problem is \r<BR>\n" );
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document.write( "3 with exponent of x+4 = 7 with exponent of 2x-1\r<BR>\n" );
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document.write( "Through all my notes I am finding nothing like this, my exmples are where I would take 3 as my base for 2nd equation </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #656950 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=656950\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3 with exponent of x+4 = 7 with exponent of 2x-1 <BR>\n" );
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document.write( "3^(x+4) = 7^(2x-1)<BR>\n" );
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document.write( "Since the variable is in the exponent, take the log::<BR>\n" );
document.write( "(x+4)*log(3) = (2x-1)*log(7)<BR>\n" );
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document.write( "Now, get the x terms together::<BR>\n" );
document.write( "x(log3-2*log(7)) = log(7)-4log(3)<BR>\n" );
document.write( "x(-1.213) = -1.063<BR>\n" );
document.write( "x = 0.877<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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