document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1042035>Question 1042035</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 4 less than twice the width. The area of the rectangle is 70 square feet. Find the dimensions of the rectangle.\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #656934 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel555><B>jorel555(1290)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel555><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=656934\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If w is the width, then the length is 2w-4. So:<BR>\n" );
document.write( "w(2w-4)=70<BR>\n" );
document.write( "2w²-4w-70=0<BR>\n" );
document.write( "w²-2w-35=0<BR>\n" );
document.write( "(w+5)(w-7)=0<BR>\n" );
document.write( "w=-5, 7<BR>\n" );
document.write( "If the width is 7, then the length is 10.<BR>\n" );
document.write( "7 x 10=70. &#9786;&#9786;&#9786;&#9786; </SPAN>\n" );
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