document.write( "Question 1041906: divide 184 in 2 parts such one-third may exceed one-seventh of another part by 8
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Algebra.Com's Answer #656932 by rothauserc(4718)\"\" \"About 
You can put this solution on YOUR website!
we have two equations in two unknowns, let x be one part and y be the other part
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\n" ); document.write( "1) x + y = 184
\n" ); document.write( "2) (x/3) = (y/7) + 8
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\n" ); document.write( "solve 1) for x and substitute for x in 2)
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\n" ); document.write( "x = 184 - y
\n" ); document.write( "( (184 - y) / 3 ) = (y/7) + 8
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\n" ); document.write( "multiply both sides of = by 21
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\n" ); document.write( "7(184-y) = 3y + 168
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\n" ); document.write( "1288 -7y = 3y + 168
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\n" ); document.write( "10y = 1120
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\n" ); document.write( "y = 112
\n" ); document.write( "x = 72
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\n" ); document.write( "to check this substitute for x and y in 2)
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\n" ); document.write( "72/3 = 112/7 + 8
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\n" ); document.write( "24 = 16 + 8
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\n" ); document.write( "24 = 24
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\n" ); document.write( "answer checks :-)
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