document.write( "Question 1041846: Show that
\n" ); document.write( "A = (A*logA*10^(logB/A^3 + 3logA)) / (-B*log1/A)
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Algebra.Com's Answer #656840 by robertb(5830)\"\" \"About 
You can put this solution on YOUR website!
\"%28A%2AlogA%2A10%5E%28log%28B%2FA%5E3%29%2B3logA%29+%29%2F%28-B%2Alog%281%2FA%29%29\"\r
\n" ); document.write( "\n" ); document.write( "= \"%28A%2AlogA%2A10%5E%28log%28B%2FA%5E3%29+%2B+logA%5E3%29+%29%2F%28-B%2Alog%281%2FA%29%29\"\r
\n" ); document.write( "\n" ); document.write( "= \"%28A%2AlogA%2A10%5E%28log%28%28B%2FA%5E3%29%2AA%5E3%29%29+%29%2F%28B%2AlogA%29\"\r
\n" ); document.write( "\n" ); document.write( "= \"%28A%2AlogA%2A10%5E%28logB%29%29%2F%28B%2AlogA%29\"\r
\n" ); document.write( "\n" ); document.write( "= \"%28A%2AlogA%2AB%29%2F%28B%2AlogA%29\"\r
\n" ); document.write( "\n" ); document.write( "= A
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