document.write( "Question 1041832: Ashely has dimes, nickels, and quarters. The number of dimes is 3 more than 2 times the number of nickels. The number of quarters is three times the number of dimes. If the coins are worth a total of $14.80, how many of each kind does she have? \n" ); document.write( "
Algebra.Com's Answer #656755 by jorel555(1290) ![]() You can put this solution on YOUR website! Let n equal nickels. Then dimes equal 2n+3; and quarters are 3(2n+3), or 6n+9. So: \n" ); document.write( "5n+10(2n+3)+25(6n+9)=1480 \n" ); document.write( "175n+255=1480 \n" ); document.write( "175n=1225 \n" ); document.write( "n=7 \n" ); document.write( "2n+3=17 \n" ); document.write( "6n+9=51 \n" ); document.write( "Ashely has 7 nickels, 17 dimes, and 51 quarters. ☺☺☺☺ \n" ); document.write( " |