document.write( "Question 1041794: If there are 80 cows and hens and 208 legs, how many cows and hens
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Algebra.Com's Answer #656716 by Edwin McCravy(20056) $\"\"$ $\"About$

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If there are 80 cows and hens and 208 legs, how many cows and hens
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document.write( "Two ways.  Without algebra and with algebra:\r\n" );
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document.write( "Here's the way without algebra:\r\n" );
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document.write( "Cows and hens both have 2 front legs each,  but cows also\r\n" );
document.write( "have two back legs each.\r\n" );
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document.write( "So since there are 80 animals there are 2•80 or 160 front legs.\r\n" );
document.write( "The remaining 208-160=48 legs have to be back legs on the cows.\r\n" );
document.write( "There are two back legs on each cow, so we divide 48 by 2 to get\r\n" );
document.write( "the number of cows:\r\n" );
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document.write( "So there are 48÷2 = 24 cows and the remaining 80-24=56 animals are hens.\r\n" );
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document.write( "Here's the way with algebra:\r\n" );
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document.write( "Let C = the number of cows\r\n" );
document.write( "Let H = the number of hens.\r\n" );
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document.write( "Then\r\n" );
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document.write( "C + H = 80\r\n" );
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document.write( "Then the number of cows' feet = 4C\r\n" );
document.write( "And the number of hens' feet = 2H\r\n" );
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document.write( "So\r\n" );
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document.write( "4C+2H = 208\r\n" );
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document.write( "Solve this system by substitution or elimination (addition):\r\n" );
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document.write( "and you'll get the same answer as with no algebra.\r\n" );
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document.write( "Edwin

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