document.write( "Question 1041673: Given a triangle whose vertices are A(4,-4) B(10,-4) and C(2,6). Find the point on each median that is two-thirds of the distance from the vertex to the midpoint of the opposite side. \n" ); document.write( "

Algebra.Com's Answer #656677 by ikleyn(52788) $\"\"$ $\"About$

You can put this solution on YOUR website!
.
\n" ); document.write( "Given a triangle whose vertices are A(4,-4) B(10,-4) and C(2,6). Find the point on each median that is two-thirds
\n" ); document.write( "of the distance from the vertex to the midpoint of the opposite side.
\n" ); document.write( "~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "

\r\n" );
document.write( "Actually, this point (intersection of medians of a triangle) is the \"centroid of the triangle\", or \"center of mass of the triangle\". \r\n" );
document.write( "\r\n" );
document.write( "See the lesson The Centroid of a triangle is the Intersection point of its medians in this site.\r\n" );
document.write( "\r\n" );
document.write( "And its coordinates are \r\n" );
document.write( "\r\n" );
document.write( " =  =  =  = ,\r\n" );
document.write( "\r\n" );
document.write( " =  =  =  = .\r\n" );
document.write( "

\n" ); document.write( " \n" ); document.write( "

\n" );