document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=90474>Question 90474</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me figure out how to do this problem. Thanks\r<BR>\n" );
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document.write( "sqrt(x+21) =5 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #65667 by </B><A HREF=/tutors/aboutme.mpl?userid=bucky><B>bucky(2189)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=bucky><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=65667\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Problem:<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%28x%2B21%29+=5 ALIGN=MIDDLE  ALT=\"sqrt%28x%2B21%29+=5\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "solve for x.<BR>\n" );
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document.write( "Begin by squaring both sides. When you do that the equation becomes:<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28sqrt%28x%2B21%29%29%5E2+=+5%5E2 ALIGN=MIDDLE  ALT=\"%28sqrt%28x%2B21%29%29%5E2+=+5%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "which becomes:<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+%2B+21+=+25 ALIGN=MIDDLE  ALT=\"x+%2B+21+=+25\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "solve for x by subtracting 13 from both sides to get:<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+25+-+21+=+4 ALIGN=MIDDLE  ALT=\"x+=+25+-+21+=+4\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "The solution, therefore, is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+4 ALIGN=MIDDLE  ALT=\"x+=+4\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "Check by substituting 12 for x in the original equation:<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28sqrt%284+%2B+21%29%29+=+5 ALIGN=MIDDLE  ALT=\"%28sqrt%284+%2B+21%29%29+=+5\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "Add the terms in the parentheses:<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28sqrt%2825%29%29+=+5 ALIGN=MIDDLE  ALT=\"%28sqrt%2825%29%29+=+5\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "The square root of 25 results in +5, so the equation is true and the answer x = 4 works.<BR>\n" );
document.write( ". <BR>\n" );
document.write( "This is the third problem of this type that you posted.  By now you should have become<BR>\n" );
document.write( "familiar with the process of solving equations of this type.  Just remember that when you<BR>\n" );
document.write( "square a square root of a quantity, the result is just the quantity itself. For example,<BR>\n" );
document.write( "the square of the square root of B is just B itself.  If you are familiar with the exponential<BR>\n" );
document.write( "form of roots and the way to multiply exponents you can look at problems of this sort in<BR>\n" );
document.write( "the following way:<BR>\n" );
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document.write( "The square root of a quantity is the same as the quantity raised to the exponent <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1%2F2 ALIGN=MIDDLE  ALT=\"1%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" >.<BR>\n" );
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document.write( "In this problem the quantity is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%2B21 ALIGN=MIDDLE  ALT=\"x%2B21\"   DISABLED_style= \"max-width:90%; height:auto;\" >. To take the square root you just raise this<BR>\n" );
document.write( "quantity to the power <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1%2F2 ALIGN=MIDDLE  ALT=\"1%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" > and this is the same as the square root. This can be<BR>\n" );
document.write( "written as:<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%28x%2B21%29+=+%28x%2B21%29%5E%281%2F2%29 ALIGN=MIDDLE  ALT=\"sqrt%28x%2B21%29+=+%28x%2B21%29%5E%281%2F2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "Then you can square the right side of this (squaring the square root of (x + 21) by multiplying<BR>\n" );
document.write( "the right side by itself. In other words the right side is squared if you do the following<BR>\n" );
document.write( "multiplication:<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28x%2B21%29%5E%281%2F2%29%2A%28x%2B21%29%5E%281%2F2%29 ALIGN=MIDDLE  ALT=\"%28x%2B21%29%5E%281%2F2%29%2A%28x%2B21%29%5E%281%2F2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "And by the rules of exponents to multiply these two quantities you just add the two exponents <BR>\n" );
document.write( "to get:<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28x%2B21%29%5E%281%2F2%29%2A%28x%2B21%29%5E%281%2F2%29+=+%28x%2B21%29%5E%281%2F2%2B1%2F2%29+=+%28x%2B21%29%5E1+=+x+%2B+21 ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "If you follow this, then you can say that the square of <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%28x%2B21%29 ALIGN=MIDDLE  ALT=\"sqrt%28x%2B21%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > equals <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%2B21 ALIGN=MIDDLE  ALT=\"x%2B21\"   DISABLED_style= \"max-width:90%; height:auto;\" >.<BR>\n" );
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document.write( "Hope this also helps you to understand the problem a little better. </SPAN>\n" );
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