document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1041724>Question 1041724</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In a recent survey 45% of students at a school said they love Italian ice. If the margin of error was 4.3%, then roughly how many students were surveyed? <BR>\n" );
document.write( "A.) 973 students<BR>\n" );
document.write( "B.) 535 students<BR>\n" );
document.write( "C.) 133 students<BR>\n" );
document.write( "D.) 243 students </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #656669 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=656669\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Since no confidence interval is stated, we can assume a 95% confidence interval<BR>\n" );
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document.write( "Margin of Error(ME) at 95% = 0.043 = 1.96 * square root( (0.45 * 0.55) / n )<BR>\n" );
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document.write( "0.022 = square root(0.2475 / n)<BR>\n" );
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document.write( "0.000484 = 0.2475 / n<BR>\n" );
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document.write( "n = 511<BR>\n" );
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document.write( "Answer is B)<BR>\n" );
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