document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1041720>Question 1041720</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Using Distance + Rate * Time. Two trucks leave warehouses that are 540 miles apart traveling toward one another.  They meet 4 hours late.  The first truck was traveling 15 mph slower than the second truck. How fast was each truck traveling? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #656657 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=656657\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The total distance is 540 miles<BR>\n" );
document.write( "speed of first truck is x mph and he drives 4 hours so distance is 4x miles<BR>\n" );
document.write( "speed of second truck is (x+15) mph, and he drives 4 hours, so distance is 4x+60 miles.  Note, first truck is driving slower than the second truck; one could use (x-15) for first truck and x for the second.\r<BR>\n" );
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document.write( "4x+4x+60=540<BR>\n" );
document.write( "8x+60=540<BR>\n" );
document.write( "subtract 60 from both sides<BR>\n" );
document.write( "8x=480<BR>\n" );
document.write( "divide both sides by 8<BR>\n" );
document.write( "x=60 mph, first truck<BR>\n" );
document.write( "(x+15)=75 mph, second truck<BR>\n" );
document.write( "In 4 hours, the first truck travels 60*4=240 miles<BR>\n" );
document.write( "the second truck travels 75*4=300 miles<BR>\n" );
document.write( "That is 540 miles </SPAN>\n" );
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