document.write( "Question 90476: Please help me figure out how to do this problem. Thanks\r
\n" ); document.write( "\n" ); document.write( "sqrt(x+13) =5
\n" ); document.write( "

Algebra.Com's Answer #65664 by bucky(2189)\"\" \"About 
You can put this solution on YOUR website!
Problem:
\n" ); document.write( ".
\n" ); document.write( "\"sqrt%28x%2B13%29+=5\"
\n" ); document.write( ".
\n" ); document.write( "solve for x.
\n" ); document.write( ".
\n" ); document.write( "Begin by squaring both sides. When you do that the equation becomes:
\n" ); document.write( ".
\n" ); document.write( "\"%28sqrt%28x%2B13%29%29%5E2+=+5%5E2\"
\n" ); document.write( ".
\n" ); document.write( "which becomes:
\n" ); document.write( ".
\n" ); document.write( "\"x+%2B+13+=+25\"
\n" ); document.write( ".
\n" ); document.write( "solve for x by subtracting 13 from both sides to get:
\n" ); document.write( ".
\n" ); document.write( "\"x+=+25+-+13+=+12\"
\n" ); document.write( ".
\n" ); document.write( "The solution, therefore, is \"x+=+12\"
\n" ); document.write( ".
\n" ); document.write( "Check by substituting 12 for x in the original equation:
\n" ); document.write( ".
\n" ); document.write( "\"%28sqrt%2812+%2B+13%29%29+=+5\"
\n" ); document.write( ".
\n" ); document.write( "Add the terms in the parentheses:
\n" ); document.write( ".
\n" ); document.write( "\"%28sqrt%2825%29%29+=+5\"
\n" ); document.write( ".
\n" ); document.write( "The square root of 25 results in +5, so the equation is true and the answer x = 12 works.
\n" ); document.write( ".
\n" ); document.write( "Hope this helps you to understand the problem.
\n" ); document.write( "
\n" );