document.write( "Question 1041572: a car is observed traveling between point a and point b in 3 seconds
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document.write( "it is known that the car is traveling at a steady speed of 25 mph\r
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document.write( "a second car is observed traveling between point a and point b in 1.5 seconds\r
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document.write( "what is the speed of the 2nd car? \r
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document.write( "what is the speed of the 3rd card observed to traverse the points in 2 seconds?
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Algebra.Com's Answer #656628 by jorel555(1290)![]() ![]() ![]() You can put this solution on YOUR website! Since time is inversely proportional to speed: \n" ); document.write( "3/1.5=n/25 \n" ); document.write( "1.5n=75 \n" ); document.write( "n=50 mph \n" ); document.write( "The second car takes 1/2 the time, so it must be going twice as fast to cover the same distance. \n" ); document.write( "For the third car: \n" ); document.write( "3/2=n/25 \n" ); document.write( "2n=75 \n" ); document.write( "n=37.5 mph. ☺☺☺☺ \n" ); document.write( " \n" ); document.write( " |