document.write( "Question 1041675: Suppos 99.7% of the assembly times are between 35 and 51 minutes and the mean is still 43 what would be the standard deviation? \n" ); document.write( "
Algebra.Com's Answer #656621 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
So assume you're looking at 35-51 as the \"6%2Asigma\" spread about the mean.
\n" ); document.write( "\"6%2Asigma=51-35\"
\n" ); document.write( "\"6%2Asigma=16\"
\n" ); document.write( "\"sigma=8%2F3\"
\n" ); document.write( "
\n" ); document.write( "
\n" );