document.write( "Question 1041491: The volume of ice-cream in the cone is half the volume of the con. The cone has a 3cm radius and 14cm height. What is the depth of the ice-cream correct to two decimal place? \n" ); document.write( "

Algebra.Com's Answer #656614 by Fombitz(32388) $\"\"$ $\"About$

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The volume of a cone is,
\n" ); document.write( " $\"V=%28pi%2F3%29r%5E2%2Ah\"$
\n" ); document.write( "In this case,
\n" ); document.write( " $\"V=%28pi%2F3%29%283%29%5E2%2A14\"$
\n" ); document.write( " $\"V=42pi\"$
\n" ); document.write( "So,
\n" ); document.write( " $\"V%5BIC%5D=42pi%2F2=21pi\"$
\n" ); document.write( "There is also a relationship between the radius and the height of the ice cream within the cone.
\n" ); document.write( "When $\"r=3\"$ , $\"h=14\"$ and when $\"r=0\"$ , $\"h=0\"$
\n" ); document.write( "So then,
\n" ); document.write( " $\"r%5BIC%5D=%283%2F14%29h%5BIC%5D\"$
\n" ); document.write( "So calculating the ice cream volume,
\n" ); document.write( " $\"%28pi%2F3%29r%5BIC%5D%5E2%2Ah%5BIC%5D=1pi\"$
\n" ); document.write( "Substituting,
\n" ); document.write( " $\"%28pi%2F3%29%283%2F14%29%5E2%2Ah%5BIC%5D%5E2%2Ah%5BIC%5D=21pi\"$
\n" ); document.write( " $\"h%5BIC%5D%5E3=1372\"$
\n" ); document.write( " $\"h%5BIC%5D=%281372%29%5E%281%2F3%29\"$
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\n" ); document.write( "I leave it to you to get the decimal equivalent of the cube root.
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