document.write( "Question 90454This question is from textbook elementary algebra
\n" ); document.write( ": solve by substitution method:\r
\n" ); document.write( "\n" ); document.write( "x=y+3
\n" ); document.write( "3x-2y=4
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Algebra.Com's Answer #65658 by malakumar_kos@yahoo.com(315)\"\" \"About 
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\r
\n" ); document.write( "\n" ); document.write( " solve by substitution method:
\n" ); document.write( "x=y+3
\n" ); document.write( "3x-2y=4
\n" ); document.write( " x = y+3..........(1)\r
\n" ); document.write( "\n" ); document.write( " 3x-2y = 4...........(2)\r
\n" ); document.write( "\n" ); document.write( " substituting for x from eq'n (1) in eq'n (2) we get
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\n" ); document.write( " 3(y+3)-2y = 4\r
\n" ); document.write( "\n" ); document.write( " 3y+9-2y = 4\r
\n" ); document.write( "\n" ); document.write( " y = -9+4 = -5\r
\n" ); document.write( "\n" ); document.write( " substitute for y in eq'n(1) we get x = -5+3 = -2\r
\n" ); document.write( "\n" ); document.write( " The solution for the given eq'ns is x = -2 and y = -5
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