document.write( "Question 1041495: Sketch the following questions. Involving parabola..\r
\n" ); document.write( "\n" ); document.write( " A satellite dish has a shape called a paraboloid,where each cross-section is a parabola. Since radio signals (parallel to the axis) will bounce off the surface of the dish to the focus, the receiver should be placed at the focus. How far should a receiver be from the vertex, if the dish is 12 ft. across 4.5 ft. deep at the vertex?
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Algebra.Com's Answer #656568 by josgarithmetic(39623)\"\" \"About 
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Examine a cross section, having vertex imagined as a minimum if on a cartesian system. A point is ( 12/2, 4.5 ). TThe vertex at the origin. Recall, this is a parabola.\r
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\n" ); document.write( "Change information into standard form equation for the parabola.\r
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\n" ); document.write( "Find how far p, is the focus from the vertex, based on the typical model derived equation, \"4py=%28x-0%29%5E2\"; this may require some care, but otherwise not too difficult.\r
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\n" ); document.write( "Parabola with vertex as minimum, symmetry axis parallel to the y-axis, \"y=a%28x-h%29%5E2%2Bk\" as standard form; vertex is (h,k).
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\n" ); document.write( "Using given focus and directrix to derive an equation for a parabola having symmetry axis parallel to the y-axis will be of a form \"4p%28y-k%29=%28x-h%29%5E2\", and the value p is how far the focus is from the vertex. Look at and study your lesson on this.
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