document.write( "Question 1041495: Sketch the following questions. Involving parabola..\r
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document.write( " A satellite dish has a shape called a paraboloid,where each cross-section is a parabola. Since radio signals (parallel to the axis) will bounce off the surface of the dish to the focus, the receiver should be placed at the focus. How far should a receiver be from the vertex, if the dish is 12 ft. across 4.5 ft. deep at the vertex? \n" );
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Algebra.Com's Answer #656568 by josgarithmetic(39623)![]() ![]() ![]() You can put this solution on YOUR website! Examine a cross section, having vertex imagined as a minimum if on a cartesian system. A point is ( 12/2, 4.5 ). TThe vertex at the origin. Recall, this is a parabola.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(1) \n" ); document.write( "Change information into standard form equation for the parabola.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(2) \n" ); document.write( "Find how far p, is the focus from the vertex, based on the typical model derived equation, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-- \n" ); document.write( "Parabola with vertex as minimum, symmetry axis parallel to the y-axis, \n" ); document.write( "- \n" ); document.write( "Using given focus and directrix to derive an equation for a parabola having symmetry axis parallel to the y-axis will be of a form |