document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=90455>Question 90455</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0072538953/algebrahomeworkh>elementary algebra</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> solve by addition method:<BR>\n" );
document.write( "x/3-y/2=-5/6<BR>\n" );
document.write( "x/5-y/3=-3/5 </SPAN>\n" );
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document.write( "    solve by addition method:<BR>\n" );
document.write( "x/3-y/2=-5/6<BR>\n" );
document.write( "x/5-y/3=-3/5<BR>\n" );
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document.write( "  x/3-y/2 = -5/6   l.c.m for 2,3 = 6  multiply each term by 6 we get <BR>\n" );
document.write( "  2x-3y = -5......(1)\r<BR>\n" );
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document.write( "   x/5-y/3 =-3/5    l.c.m for 3,5 = 15  multiply each term by 15 we get \r<BR>\n" );
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document.write( "  3x-5y =-9........(2)\r<BR>\n" );
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document.write( "    -3(2x-3y = -5)    (multiply eq'n (1) by -3)\r<BR>\n" );
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document.write( "     -6x+9y = 15......(3)\r<BR>\n" );
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document.write( "    2(3x-5y=-9)     (multiply  eq'n (2) by 2)\r<BR>\n" );
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document.write( "    6x-10y  = -18.....(4)\r<BR>\n" );
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document.write( " adding eq'n(3)  and eq'n (4) we get -y =-3  or y =3\r<BR>\n" );
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document.write( " substitute the value of y in eq'n(3) -6x+9*3 = 15\r<BR>\n" );
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document.write( "                -6x+27-15 = 0\r<BR>\n" );
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document.write( "                   12 = 6x or x = 12/6 = 2\r<BR>\n" );
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document.write( "  The required solution is x = 2  and y = 3   </SPAN>\n" );
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